Medians in triangle

Median of isosceles triangle has a length 3 cm. Determine the length of its sides if its perimeter is 16 cm.

Result

a =  5 cm
b =  5 cm
c =  6 cm

Solution:

a=(16−2⋅ 3)/2=5 cma=(16-2 \cdot \ 3)/2=5 \ \text{cm}
b=(16−2⋅ 3)/2=5 cmb=(16-2 \cdot \ 3)/2=5 \ \text{cm}
c=2⋅3=6 cm  a+b+c=16 a+b=10 a=b=10/2=5c = 2\cdot 3 = 6 \ \text{cm} \ \\ \ \\ a+b +c = 16 \ \\ a+b = 10 \ \\ a=b = 10/2 = 5

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