Digits A, B, C

For the various digits A, B, C is true: the square root of the BC is equal to the A and sum B+C is equal to A. Calculate A + 2B + 3C. (BC is a two-digit number, not a product).

Correct result:

A+2B+3C =  28

Solution:

0A,B,C9 BC=A B+C=A  10B+C=A2 A=9 B=8 C=1 A+2B+3C=9+28+31=28 



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