Height difference

What height difference overcome if we pass road 1 km long with a pitch21 per mille?

Result

x =  20.995 m

Solution:

tan⁡α=21/1000 α=arctan⁡21/1000=0∘1′16"  x=1000sin⁡α=20.995 m\tan \alpha = 21/1000 \ \\ \alpha = \arctan 21/1000 = 0^\circ 1'16" \ \\ \ \\ x = 1000 \sin \alpha = 20.995 \ \text{m}

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