# Demographics

The population grew in the city in 10 years from 42000 to 54500. What is the average annual percentage increase of population?

Result

p =  2.6 %

#### Solution:

$p = 100 ( e^{ \dfrac{ ln \dfrac{ 54500}{ 42000}}{ 10}} -1) \doteq 2.6 \% \ \\$

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