The Earth

The Earth's surface is 510,000,000 km2. Calculates the radius, equator length, and volume of the Earth, assuming the Earth has the shape of a sphere.

Correct result:

r =  6370.597 km
o =  40027.641 km
V =  1083001373865.8 km3

Solution:

S=510000000 km2 S=4 πr2  r=S4π=5100000004 3.1416=6370.597 kmS=510000000 \ \text{km}^2 \ \\ S=4 \ \pi r^2 \ \\ \ \\ r=\sqrt{ \dfrac{ S }{ 4 \pi } }=\sqrt{ \dfrac{ 510000000 }{ 4 \cdot \ 3.1416 } }=6370.597 \ \text{km}
o=2π r=2 3.1416 6370.5973=40027.641 kmo=2 \pi \cdot \ r=2 \cdot \ 3.1416 \cdot \ 6370.5973=40027.641 \ \text{km}
V=43 π r3=43 3.1416 6370.59733=1083001373865.8 km3=1.0830011012 km3V=\dfrac{ 4 }{ 3 } \cdot \ \pi \cdot \ r^3=\dfrac{ 4 }{ 3 } \cdot \ 3.1416 \cdot \ 6370.5973^3=1083001373865.8 \ \text{km}^3=1.083001\cdot 10^{ 12 } \ \text{km}^3



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