Double probability

The probability of success of the planned action is 60%. What is the probability that success will be achieved at least once if this action is repeated twice?

Result

p =  0.84

Solution:

p1=60%=60100=0.6  p=p1+p1−p1⋅ p1=0.6+0.6−0.6⋅ 0.6=2125=0.84p_{1}=60 \%=\dfrac{ 60 }{ 100 }=0.6 \ \\ \ \\ p=p_{1}+p_{1} - p_{1} \cdot \ p_{1}=0.6+0.6 - 0.6 \cdot \ 0.6=\dfrac{ 21 }{ 25 }=0.84

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