Forces

Determine the resultant of two perpendicular forces F1 = 560 N and second force of 25% smaller.

Result

F =  700 N

Solution:

F=5602+(560⋅ 0.75)2=700 NF=\sqrt{ 560^{ 2 }+(560 \cdot \ 0.75)^{ 2 } }=700 \ \text{N}

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