Two forces

The two forces F1 = 580N and F2 = 630N, have an angle of 59 degrees. Calculate their resultant force, F.

Correct result:

F =  1053.4182 N

Solution:

$$\begin{gathered} F_1=580\text{ N } \\ {F}_2=630\text{ N } \\ A=0^{\circ } \\ B=59^{\circ } \\ x=F_1\cdot \cos A^{\circ }+F_2\cdot \cos B^{\circ }=F_1\cdot \cos 0^{\circ }+F_2\cdot \cos 0^{\circ }=580\cdot \cos 0^{\circ }+630\cdot \cos 0^{\circ }=580\cdot 1+630\cdot 1=904.47399 \\ y=F_1\cdot \sin A^{\circ }+F_2\cdot \sin B^{\circ }=F_1\cdot \sin 0^{\circ }+F_2\cdot \sin 0^{\circ }=580\cdot \sin 0^{\circ }+630\cdot \sin 0^{\circ }=580\cdot 0+630\cdot 0=540.0154 \\ F=\sqrt{x^2+y^2}=\sqrt{904.474^2+540.0154^2}=1053.4182\text{ N} \end{gathered}$$

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Dr Math

checkout our new two vector sum calculator:

https://www.hackmath.net/en/calculator/sum-of-the-two-vectors?a=580&b=630&a1=59&submit=1

2 years ago  Like

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