Hiker and cyclist

At 7 PM hiker started at 6 km/h to hike. After 3 hrs. later started on the same trip cyclist at speed of 15 km/h. After an hour of driving a flat tire and take him half hours to correct defect. At what time catch up cyclist with hiker?

Result

t = 12:50 h Wrong answer

Solution:


6(t-7.00) = 15(t-(7.00+3.00+0.5))

6•(t-7.00) = 15•(t-(7.00+3.00+0.5))

9t = 115.5

t = 77/6 ≈ 12.833333

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