Soup

On Monday we cook 25 pots and 10 boilers of soup. On Tuesday 15 pots and 13 boilers. On Wednesday 20 pots and on Thursday 30 boilers. On Monday and Tuesday was cooked the same amount of soup. How many times more soup cooked on Thursday than on Wednesday?

Result

n =  5

Solution:

2a+10b=15a+13b 10a=3b a=310b n=30b20a=30b20⋅310b=30/6=52a + 10b = 15a +13b \ \\ 10a = 3b \ \\ a = \dfrac{3}{10} b \ \\ n = \dfrac{30b}{20a} = \dfrac{30b}{20 \cdot \dfrac{3}{10} b } = 30/6 = 5

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