Eight small Christmas balls with a radius of 1 cm have the same volume as one large Christmas ball. What has a bigger surface: eight small balls or one big ball?

Correct answer:

x =  8

Step-by-step explanation:

n=8 r=1 cm  V1=n 34 π r3=8 34 3.1416 1333.5103 cm3  V2=V1=33.510333.5103 cm3  V2=34 π r23  r2=33 V2/4/π=33 33.5103/4/3.1416=2 cm  S1=n 4π r2=8 4 3.1416 12100.531 cm2 S2=4π r22=4 3.1416 2250.2655 cm2  S1>S2  x=8

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