Reconstruction of the corridor

Calculate how many minutes will be reduced to travel 187 km long railway corridor, where the maximum speed increases from 120 km/h to 160 km/h.

Calculate how many minutes will shorten travel time, if we consider that the train must stop at 6 stations, each station with the equally slow 0.8 m/s2 and from station accelerates 0.5 m/s2?

What is the average speed before and after reconstruction, if the train stays for 2 minutes in every station?

Consider the intermediate stops are so long that the train will always reach the speed limit.

Correct answer:

t1 =  23.375 min
t2 =  20.9444 min
v1 =  0 km/h
v2 =  0 km/h

Step-by-step explanation:

v1=187/(T1+6/30)=187/(1.6637+6/30)100.3403=0 km/h
v2=187/(T2+6/30)=187/(1.3146+6/30)123.4663=0 km/h



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