Three ints

The sum of three consecutive integers is 2016. What numbers are they?

Result

a =  671
b =  672
c =  673

Solution:


a+b+c=2016
b = a+1
c = b+1

a+b+c = 2016
a-b = -1
b-c = -1

a = 671
b = 672
c = 673

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