Track surface fitting

The circular running track has a diameter of 130 meters. Can a rectangular surface with dimensions of 12 m and 50 m be grassed inside the circle?

Final Answer:

x =  1

Step-by-step explanation:

$$\begin{gathered} D=130\text{m} \\ a=12\text{m} \\ b=50\text{m} \\ u=\sqrt{a^2+b^2}=\sqrt{12^2+50^2}=2\sqrt{661}\text{m}\doteq 51.4198\text{m} \\ u<D \\ x=1 \end{gathered}$$

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