If one liter of paint covers an area of 5 m2, how much paint is needed to cover:
a) rectangular swimming pool With dimensions of 4m x 3m x 2.5m (the Inside walls and the floor only)
b) the Inside walls and floor of a cylindrical reservoir with a diameter of 3m and height of 2.5 m. If one liter of paint costs 72, how much will the painter spend to pant the swimming pool and reservoir

Correct answer:

V1 =  9.4 l
V2 =  6.1261 l
m =  1117.8796

Step-by-step explanation:

a=4 m b=3 m c=2.5 m  S1=a b+2 (a+b) c=4 3+2 (4+3) 2.5=47 m2 u=5 l/m2 V1=S1/u=47/5=9.4 l
D=3 m h=2.5 m r=D/2=3/2=23=1.5 m S2=π r2+π D h=3.1416 1.52+3.1416 3 2.530.6305 m2 V2=S2/u=30.6305/5=6.1261 l
m=72 (V1+V2)=72 (9.4+6.1261)=1117.8796

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