If one

If one litre of pant covers an area of 5 m2 how much paint is needed to cover:

a) rectangular swimming pool With dimensions 4m x 3m x 2.5m (the Inside walls and the floor only)

b) the Inside walls and floor of a cylindrical reservoir with diameter 3m and height 2.5m

If one liter of paint costs 72, how much will the painter spend to pant the swimming pool and reservoir

Result

V1 =  9.4 l
V2 =  6.126 l
m =  1117.872

Solution:

a=4 m b=3 m c=2.5 m  S1=a b+2 (a+b) c=4 3+2 (4+3) 2.5=47 m2 u=5 l/m2 V1=S1/u=47/5=475=9.4 la=4 \ \text{m} \ \\ b=3 \ \text{m} \ \\ c=2.5 \ \text{m} \ \\ \ \\ S_{1}=a \cdot \ b + 2 \cdot \ (a+b) \cdot \ c=4 \cdot \ 3 + 2 \cdot \ (4+3) \cdot \ 2.5=47 \ \text{m}^2 \ \\ u=5 \ \text{l/m}^2 \ \\ V_{1}=S_{1} / u=47 / 5=\dfrac{ 47 }{ 5 }=9.4 \ \text{l}
D=3 m h=2.5 m r=D/2=3/2=32=1.5 m S2=π r2+π D h=3.1416 1.52+3.1416 3 2.530.6305 m2 V2=S2/u=30.6305/56.12616.126 lD=3 \ \text{m} \ \\ h=2.5 \ \text{m} \ \\ r=D/2=3/2=\dfrac{ 3 }{ 2 }=1.5 \ \text{m} \ \\ S_{2}=\pi \cdot \ r^2 + \pi \cdot \ D \cdot \ h=3.1416 \cdot \ 1.5^2 + 3.1416 \cdot \ 3 \cdot \ 2.5 \doteq 30.6305 \ \text{m}^2 \ \\ V_{2}=S_{2} / u=30.6305 / 5 \doteq 6.1261 \doteq 6.126 \ \text{l}
m=72 (V1+V2)=72 (9.4+6.1261)=1117.872m=72 \cdot \ (V_{1}+V_{2})=72 \cdot \ (9.4+6.1261)=1117.872



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