Triangle 2668

The triangle ABC has side lengths a = 14 cm, b = 20 cm, c = 7.5 cm. Find the sizes of the angles and the area of this triangle.

Correct answer:

S =  37.3078 cm2
α =  29.8306 °
β =  134.7142 °
γ =  15.4552 °

Step-by-step explanation:

a=14 cm b=20 cm c=7.5 cm s=2a+b+c=214+20+c=214+20+7.5=483=20.75 cm  S=s (sa) (sb) (sc)=20.75 (20.7514) (20.7520) (20.757.5)=37.3078 cm2

Try calculation via our triangle calculator.

k=π180=3.141618057.2958 α=k arccos(2 c ba2+b2+c2)=57.2958 arccos(2 7.5 20142+202+7.52)=29.8306=29°4950"
β=k arccos(2 a ca2b2+c2)=57.2958 arccos(2 14 7.5142202+7.52)=134.7142=134°4251"
γ=k arccos(2 a ba2+b2c2)=57.2958 arccos(2 14 20142+2027.52)=15.4552=15°2719"



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