# Meneal's 26771

Show (using Meneal's theorem) that the center of gravity divides the line in a 1:2 ratio.

## Correct answer:

Tips for related online calculators

### You need to know the following knowledge to solve this word math problem:

We encourage you to watch this tutorial video on this math problem: video1

## Related math problems and questions:

- Ratio of triangles areas

In an equilateral triangle ABC, the point T is its center of gravity, the point R is the image of the point T in axial symmetry along the line AB, and the point N is the image of the point T in axial symmetry along the line BC. Find the ratio of the areas - Isosceles 5575

The picture shows an isosceles triangle VLK with a center of gravity of T. The base VL measures 16 cm, and the line KK1 measures 18 cm. How long is the VV1 line? - Center

In the ABC triangle is point D[1,-2,6], which is the center of the |BC|, and point G[8,1,-3], which is the center of gravity of the triangle. Find the coordinates of the vertex A[x,y,z]. - Triangle 69144

The line p passes through the center of gravity T of the triangle and is parallel to the line BC. What is the ratio of the area of the divided smaller part of the triangle by the line p? What is the area of the triangle?

- The triangle

Three vertices give the triangle: A [0.0] B [-4.2] C [-6.0] Calculate V (intersection of heights), T (center of gravity), O - the center of a circle circumscribed - Calculate 4425

In the triangle ABC with the center of gravity T, b = 7cm, median to c: tc = 9cm, the ATC angle is 112 degrees. Calculate the length of the line ta. - Center of gravity

In the isosceles triangle ABC is the ratio of the lengths of AB and the height to AB 10:12. The arm has a length of 26 cm. If the center of gravity is T, find the area of the triangle ABT.