Gold wire

From one gram of gold was pulled wire 2.1 km length. What is it diameter if density of Au is ρ=19.5 g/cm3?

Result

d =  5.58 μm

Solution:

$d = \dfrac{ 4m}{ \pi\rho l} = 100 \sqrt{ \dfrac{ 4 \cdot 1}{ \pi \cdot 19.5\cdot 2.1 \cdot 10}} = 5.58 \ \mu m$

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