Rotating cone II

Calculate area of surface of rotating cone with base radius r=19 cm and height h=9 cm.

Correct answer:

S =  23.89 dm²

Step-by-step explanation:

$$\begin{gathered} S=S_1+S_2=\pi \cdot 19^2+\pi \cdot 19\cdot \sqrt{9^2+19^2} \\ S=2389.031c{m}^2=23.89{\text{dm}}^2 \end{gathered}$$

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