Frustrum - volume, area

Calculate the surface and volume of a truncated rotating cone with base radii of 8 cm and 4 cm and a height of 5 cm.

Correct answer:

S =  492.7195 cm2
V =  586.4306 cm3

Step-by-step explanation:

r1=8 cm r2=4 cm h=5 cm  S1=π r12=3.1416 82201.0619 cm2 S2=π r22=3.1416 4250.2655 cm2 S3=π (r1+r2) h2+(r1r2)2=3.1416 (8+4) 52+(84)2241.3921 cm2  S=S1+S2+S3=201.0619+50.2655+241.3921=492.7195 cm2
V=31 (S1+π r1 r2+S2) h=31 (201.0619+3.1416 8 4+50.2655) 5=586.4306 cm3

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