Truncated cone

Calculate the volume of a truncated cone with base radiuses r₁=13 cm, r₂ = 10 cm and height v = 8 cm.

Correct answer:

V =  3342.7 cm³

Step-by-step explanation:

$$\begin{gathered} v_2={\displaystyle \frac{r_2}{r_1-r_2}}v={\displaystyle \frac{10}{13-10}}8=26.67 \\ V=V_1-V_2={\displaystyle \frac{1}{3}}\pi (r_1^2(v+v_2)-r_2^2{v}_2)=3342.7{\text{cm}}^3 \end{gathered}$$

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