Truncated cone

Calculate the volume of a truncated cone with base radiuses r1=13 cm, r2 = 10 cm and height v = 8 cm.

Correct answer:

V =  3342.7 cm3

Step-by-step explanation:

v2=r2r1r2v=1013108=26.67 V=V1V2=13π(r12(v+v2)r22v2)=3342.7 cm3 

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