Surface and volume

Calculate the surface and volume of a cylinder whose height is 8 dm and the radius of the base circle is 2 dm
 

Correct answer:

S =  125.6637 dm²
V =  100.531 dm³

Step-by-step explanation:

$$\begin{gathered} h=8\text{ dm } \\ r=2\text{ dm } \\ {S}_1=\pi \cdot r^2=3.1416\cdot 2^2\doteq 12.5664{\text{dm}}^2 \\ {S}_2=2\pi \cdot r\cdot h=2\cdot 3.1416\cdot 2\cdot 8\doteq 100.531{\text{dm}}^2 \\ S=2\cdot S_1+S_2=2\cdot 12.5664+100.531=125.6637{\text{dm}}^2 \end{gathered}$$

$V=S_1\cdot h=12.5664\cdot 8=100.531{\text{dm}}^3$

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