Isosceles triangle

Calculate the area of an isosceles triangle, the base of which measures 16 cm and the arms 10 cm.

Correct answer:

S =  48 cm²

Step-by-step explanation:

$$\begin{gathered} a=16\text{ cm } \\ r=10\text{ cm } \\ h=\sqrt{r^2-(a\mathrm{/}2{)}^2}=\sqrt{10^2-(16\mathrm{/}2{)}^2}=6\text{ cm } \\ S={\displaystyle \frac{a\cdot h}{2}}={\displaystyle \frac{16\cdot 6}{2}}=48{\text{cm}}^2 \end{gathered}$$

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