A section

A section of the boardwalk is made of 15 boards. Each board is 9 1/4 inches wide. The total width of the boardwalk is 144 inches. The spacing between each board is equal. What is the width of the spacing between the boards?

Correct result:

s =  0.375 inch

Solution:

$$\begin{gathered} a=9+1\mathrm{/}4={\displaystyle \frac{37}{4}}=9.25\text{ inch } \\ t=144\text{ inch } \\ n=15 \\ s=(t-n\cdot a)\mathrm{/}(n-1)=(144-15\cdot 9.25)\mathrm{/}(15-1)={\displaystyle \frac{3}{8}}={\displaystyle \frac{3}{8}}\text{ inch}=0.375\text{ inch} \end{gathered}$$

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