# Tank

To cuboid tank whose bottom has dimensions of 9 m and 15 m were flow 1080 hectoliters of water. This was filled 40% of the tank volume. Calculate the depth of the tank.

Result

h =  2 m

#### Solution:

$a = 9 \ \\ b = 15 \ \\ V = 1080 /10 = 108 \ \\ h_{ 1 } = V / (a \cdot \ b) = 108 / (9 \cdot \ 15) = \dfrac{ 4 }{ 5 } = 0.8 \ \\ h = h_{ 1 } / 0.40 = 0.8 / 0.40 = 2 = 2 \ \text{ m }$

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