Collision of bodies

From point A at a height of 2 m and from point B at a height of 6 m, two bodies are thrown at the same time towards each other. The first from point A with a horizontal speed of 8 m/s, and the second from the direction down at an angle of 45 degrees to the horizontal with such an initial speed that the bodies collide during their flight. The horizontal distance between the points A and B is 8 m. Calculate the initial speed of the body from point B, the coordinates x and y of the point of collision, the duration of the motion of the bodies until the collision, and the speed of both bodies at the moment of the collision

Final Answer:

v2 =   m/s

Step-by-step explanation:

y1=2 m y2=6 m v1=8 m/s α=90  β=45  a=8 m g=9.81 m/s2  v2=v1x=v1 sinα=v1 sin90° =8 sin90° =8 1=8 m/s= m/s



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