Collision

The two bodies, whose initial distance is 240 m, move evenly against each other consistently. The first body has an initial velocity of 4 m/s and an acceleration of 3 m/s2, the second body has an initial speed of 6 m/s and an acceleration of 2 m/s2. Find the time of collision between the bodies and the collision distance from the initial position of the first body.

Correct result:

t =  8 s
s1 =  128 m

Solution:


Our quadratic equation calculator calculates it.

s1=v1 t+12 a1 t2=4 8+12 3 82=128=128 m s2=v2 t+12 a2 t2=6 8+12 2 82=112 m s3=s1+s2=128+112=240 m



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