Motion

The two bodies move in the same direction evenly in a straight line, at speeds of 5 cm/s and 10 cm/s. The movement of the first body started 2 seconds earlier than the movement of the second body, from a point located at a distance of 20 cm from the starting point (where the second body was located). Draw a suitable chart in which you can find the place and time of the meeting.

Correct result:

s =  26.6667 cm
t =  4.6667 s

Solution:


s = 4(t+2)
s = 10t-20

s = 4•(t+2)
s = 10•t-20

s-4t = 8
s-10t = -20

s = 803 ≈ 26.666667
t = 143 ≈ 4.666667

Our linear equations calculator calculates it.
t=4.6667=143=4.6667 s



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