Cone

The rotating cone volume is 9.42 cm3, with a height 10 cm. What angle is between the side of the cone and its base?

Correct result:

α =  0 °

Solution:

V=9.42 h=10 V=Sh/3 S=3⋅ V/h=3⋅ 9.42/10=1413500=2.826 S=πr2 r=S/π=2.826/3.1416≐0.9484 α=180/π⋅ arctan⁡(h/r)=180/3.1416⋅ arctan⁡(10/0.9484)≐84.582=0∘=0∘

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