The rotating cone volume is 9.42 cm3, with a height of 10 cm. What angle is between the side of the cone and its base?

Correct answer:

α =  84.582 °

Step-by-step explanation:

V=9.42 cm3 h=10 cm  V = 3Sh  S=3 V/h=3 9.42/10=5001413=2.826 cm2 S = π r2  r=S/π=2.826/3.14160.9484 cm φ=arctan(h/r)=arctan(10/0.9484)1.4762 rad  α=φ  °=φ π180   °=1.4762 π180   °=84.582  °=84.582=84°3455"

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