The pyramid has a base rectangle with a = 6cm, b = 8cm. The side edges are the same and their length = 12.5 cm. Calculate the surface of the pyramid.


S =  215.55 cm2


a=6 cm b=8 cm s=12.5 cm  v1=s2(a/2)2=12.52(6/2)212.1347 cm v2=s2(b/2)2=12.52(8/2)211.8427 cm S1=a v1/2=6 12.1347/236.404 cm2 S2=b v2/2=8 11.8427/22 561 cm247.3709 cm2 S3=a b=6 8=48 cm2 S=2 S1+2 S2+S3=2 36.404+2 47.3709+48215.5497215.55 cm2a=6 \ \text{cm} \ \\ b=8 \ \text{cm} \ \\ s=12.5 \ \text{cm} \ \\ \ \\ v_{1}=\sqrt{ s^2-(a/2)^2 }=\sqrt{ 12.5^2-(6/2)^2 } \doteq 12.1347 \ \text{cm} \ \\ v_{2}=\sqrt{ s^2-(b/2)^2 }=\sqrt{ 12.5^2-(8/2)^2 } \doteq 11.8427 \ \text{cm} \ \\ S_{1}=a \cdot \ v_{1}/2=6 \cdot \ 12.1347/2 \doteq 36.404 \ \text{cm}^2 \ \\ S_{2}=b \cdot \ v_{2}/2=8 \cdot \ 11.8427/2 \doteq 2 \ \sqrt{ 561 } \ \text{cm}^2 \doteq 47.3709 \ \text{cm}^2 \ \\ S_{3}=a \cdot \ b=6 \cdot \ 8=48 \ \text{cm}^2 \ \\ S=2 \cdot \ S_{1}+2 \cdot \ S_{2}+S_{3}=2 \cdot \ 36.404+2 \cdot \ 47.3709+48 \doteq 215.5497 \doteq 215.55 \ \text{cm}^2

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