The factory

The factory ordered 500 hexagonal steel bars of square sections with 25 mm sides. How many cars with a load capacity of 3 tonnes will be needed for bar move if the steel density is 7,850 kg.m-3?

Correct answer:

n =  5

Step-by-step explanation:

$$\begin{gathered} h=7850 \\ V=6\cdot 0.025^2\doteq 0.0038 \\ m=500\cdot V\cdot h=500\cdot 0.0038\cdot 7850={\displaystyle \frac{58875}{4}}=14718\frac{3}{4}=14718.75 \\ n=\lceil m\mathrm{/}3000\rceil =\lceil 14718.75\mathrm{/}3000\rceil =5 \end{gathered}$$

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