Internal angles

Find the internal angles of the triangle ABC if the angle at the vertex C is twice the angle at B and the angle at the vertex B is 4 degrees smaller than the angle at vertex A.

Correct answer:

α =  48 °
β =  44 °
γ =  88 °

Step-by-step explanation:

α+β+γ=180° γ = 2β β = α4°  α+(α4)+2 (α4)=180  4α=192  α=4192=48  α=48=48
β=α4=484=44
γ=2 β=2 44=88



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algebraplanimetricsUnits of physical quantitiesGrade of the word problem

 
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