Internal angles

Find the internal angles of the triangle ABC if the angle at the vertex C is twice the angle at the B and the angle at the vertex B is 4 degrees smaller than the angle at the vertex A.

Correct result:

A =  48
B =  44
C =  88

Solution:

A+B+C=180
C = 2•B
B = A-4

A+B+C = 180
2B-C = 0
A-B = 4

A = 48
B = 44
C = 88

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