Catching up time

Johnny left home at 8 a.m. on foot at an average speed of 4 km/h. At 11 a.m., dad followed him on a bicycle at an average speed of 40 km/h. How long and at what distance from home will dad catch up with Johnny?

Final Answer:

t =  0.3333 h
s =  13.3333 km

Step-by-step explanation:

v1=4 km/h v2=40 km/h  Δt=118=3 h  s1=s2  v1(t+Δt)=v2 t 4(t+3)=40 t  4 (t+3)=40 t  36t=12  t=3612=0.33333333  t=310.333333=0.3333 h
s=v2 t=40 0.3333=13.3333 km



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