Bicycle pursuit calculation

The first patrol of the pupils' orientation run started at 8 a.m. at an average speed of 5 km/h. At 8:36 AM, the leader of the orienteering race followed them on a bicycle at a speed of 20 km/h. When and how far from the start will he catch up with them?

Result

x = 8:48 hh:mm Wrong answer
s =  4 km

Step-by-step explanation:

s=vt  5 (t8.00)=20 (t(8+36/60))  900t=7920  t=9007920=8.8  t=544=8.8  x=t=8.8=8:48 hh:mm
s=5 (t8.00)=5 (8.88.00)=4 km



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algebranumbersUnits of physical quantitiesthemes, topicsGrade of the word problem

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