Surface area of cylinder

Determine the lateral surface of the rotary cylinder which is circumscribed cube with edge length 5 cm.

Result

S =  189.612 cm2

Solution:

a=5 r=2 a/2=2 5/23.5355 h=a=5 S1=π r2=3.1416 3.5355239.2699 S2=2π r h=2 3.1416 3.5355 5111.0721 S=2 S1+S2=2 39.2699+111.0721189.6119189.612 cm2a=5 \ \\ r=\sqrt{ 2 } \cdot \ a/2=\sqrt{ 2 } \cdot \ 5/2 \doteq 3.5355 \ \\ h=a=5 \ \\ S_{1}=\pi \cdot \ r^2=3.1416 \cdot \ 3.5355^2 \doteq 39.2699 \ \\ S_{2}=2 \pi \cdot \ r \cdot \ h=2 \cdot \ 3.1416 \cdot \ 3.5355 \cdot \ 5 \doteq 111.0721 \ \\ S=2 \cdot \ S_{1} +S_{2}=2 \cdot \ 39.2699 +111.0721 \doteq 189.6119 \doteq 189.612 \ \text{cm}^2



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