Triangular pyramid

Determine the volume and surface area of a regular triangular pyramid having a base edge a=20 cm and a lateral edge b = 35 cm

Correct result:

V =  1848.4228 cm3
S =  1179.4357 cm2

Solution:

a=20 cm b=35 cm  a2=a/2=20/2=10 cm h1=b2a22=352102=15 5 cm33.541 cm h=h12a22=33.5412102=5 41 cm32.0156 cm  S1=a h1/2=20 33.541/2=150 5 cm2335.4102 cm2 S2=34 a2=34 202=100 3 cm2173.2051 cm2  V=13 S2 h=13 173.2051 32.0156=1848.4228 cm3
S=3 S1+S2=3 335.4102+173.2051=1179.4357 cm2



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