trapezoid ABCD a = 35 m, b=28 m c = 11 m and d = 14 m. How to calculate its area?

Correct result:

S =  321.9487 cm2


a=35 b=28 d=14 c=11 h>0  d2=x2+h2 b2=y2+h2 c=axy  142=x2+h2 282=y2+h2 c=35xy  x=1/4=14=0.25 y=97/4=974=24.25 c=axy=35(0.25)24.25=11  h=d2x2=142(0.25)213.9978 cm S=(a+c) h/2=(35+11) 13.9978/2=321.9487 cm2

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Showing 1 comment:
How did you come up with x = -0.25 and y = 24.25?


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