# Minute

Two boys started from one place. First went north at velocity 3 m/s and the second to the east with velocity 4 m/s. How far apart they are after minute?

Result

x =  300 m

#### Solution:

$x=\sqrt{ (3 \cdot \ 60)^2+(4 \cdot \ 60)^2 }=300 \ \text{m}$

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