Probability 37651

What is the probability that in a family with four children, there are:
a) at least three girls
b) at least one boy,

If the probability of a boy is 0.51?

Correct answer:

p1 =  0.2977
p2 =  0.9424

Step-by-step explanation:

p=0.51 C3(4)=(34)=3!(43)!4!=14=4  d3=(34) (1p)3 p1=4 (10.51)3 0.5110.24 C4(4)=(44)=4!(44)!4!=11=1  d4=(44) (1p)4 p0=1 (10.51)4 0.5100.0576  p1=d3+d4=0.24+0.0576=0.2977

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