Family

94 boys are born per 100 girls. Determine the probability that there are two boys in a randomly selected family with three children.

Correct result:

p =  36.3054 %

Solution:

p1=9494+100=47970.4845 p2=1p1=10.4845=50970.5155  C2(3)=(32)=3!2!(32)!=31=3  p=100 (32) p12 p21=100 3 0.48452 0.51551=36.3054%



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