Container weight

The weight of the water container is 2.48 kg. If we pour 75% of the water, the container with water weighs 0.98 kg. Find the weight of the empty container. How much water was originally in the container?

Final Answer:

x =  0.48 kg
y =  2 kg

Step-by-step explanation:

r=100%75%=110075=0.25  x+y = 2.48  kg x + r y = 0.98  kg  (2.48y)+r y=0.98 (2.48y)+0.25 y=0.98  0.75y=1.5  y=0.751.5=2  y=2  x=2.48y=2.482=0.48 kg



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesGrade of the word problem

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