Container with water

The weight of a container with water is 2.48 kg. Suppose the cast is 75% water, and the container with water weighs 0.98 kg. Determine the weight of the empty container. How much water was originally in the container?

Final Answer:

m =  0.48 kg
v =  2 kg

Step-by-step explanation:

r=100%−75%=1−10075​=0.25  m+v=2.48 m+r⋅ v=0.98 m+0.25⋅ v=0.98  m+v=2.48 m+0.25v=0.98  Row2−Row1→Row2 −0.75v=−1.5  v=−0.75−1.5​=2 m=2.48−v=2.48−2=0.48=0.48 kg  m=2512​=0.48 v=2

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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesGrade of the word problem

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