Find x in modulo equation:

47x = 4 (mod 9)

Hint - read as: what number 47x divided by 9 (modulo 9) give remainder 4 .

Correct answer:

x =  2

Step-by-step explanation:

47x=9k+4;k,xinteger k=(47x4)/9 k1=(47 14)/9=439=4794.7778 k2=(47 24)/9=10 k3=(47 34)/9=1379=152915.2222 k4=(47 44)/9=1849=204920.4444 . x=2

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