Find x in modulo equation:

47x = 4 (mod 9)

Hint - read as: what number 47x divided by 9 (modulo 9) give remainder 4 .

Correct result:

x =  2


47x=9k+4;k,xinteger k=(47x4)/9 k1=(47 14)/9=4394.7778 k2=(47 24)/9=10 k3=(47 34)/9=137915.2222 k4=(47 44)/9=184920.4444 . x=2

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