Acceleration 43881

I have specified that the vehicle has an acceleration of 2 m/s², and I need to find out how many meters it will travel if it reaches 64km/h and also states how long it takes for the vehicle to travel every one meter.

Correct answer:

x = 79.0123 m

Step-by-step explanation:

a = 2 m/s^{2} v = 64 km/h \to m/s = 64 : 3.6 m/s = 17.77778 m/s v = a t t = v / a = \frac{1 6 0}{9} / 2 = \frac{1 6 0}{9 \cdot 2} = \frac{1 6 0}{1 8} = \frac{8 0}{9} ≐ 8.8889 s x = \frac{1}{2} \cdot a \cdot t^{2} = \frac{1}{2} \cdot 2 \cdot \frac{8 0}{9}^{2} = \frac{6 4 0 0}{8 1} ≐ 79.0123 m Verifying Solution: s_{1} = 1 m t_{2} = 2 \cdot s_{1} / a = 2 \cdot 1 / 2 = 2 s ≐ 1.4142 s s_{2} = 2 m t_{2} = 2 \cdot s_{2} / a - t_{1} = 2 \cdot 2 / 2 - t_{1} = 2 s ≐ 1.4142 s s_{3} = 3 m t_{3} = 2 \cdot s_{3} / a - t_{1} - t_{2} = 2 \cdot 3 / 2 - t_{1} - 1.4142 ≐ 0.3178 s s_{4} = 4 m t_{4} = 2 \cdot s_{4} / a - t_{1} - t_{2} - t_{3} = 2 \cdot 4 / 2 - t_{1} - 1.4142 - 0.3178 ≐ 0.2679 s s_{5} = 5 m t_{5} = 2 \cdot s_{5} / a - t_{1} - t_{2} - t_{3} - t_{4} = 2 \cdot 5 / 2 - t_{1} - 1.4142 - 0.3178 - 0.2679 ≐ 0.2361 s s_{6} = 6 m t_{6} = 2 \cdot s_{6} / a - t_{1} - t_{2} - t_{3} - t_{4} - t_{5} = 2 \cdot 6 / 2 - t_{1} - 1.4142 - 0.3178 - 0.2679 - 0.2361 ≐ 0.2134 s

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