Concentration 4419

We added 300 g of water to a 400 g of salt solution. This reduces the solution's concentration by 5%. How much water did the original solution contain, and what was its concentration?

Correct answer:

m =  1406.4382 g
p1 =  28.4406 %

Step-by-step explanation:

m=400+w p1=400/m 100 p2=400/(m+300) 100 p2=p15 m>0 m1406.44,p128.4406,p223.4406,w1006.44 m=1406.4382416273380681=1406.4382 g
p1=400/m 100=400/1406.4382 10028.4406% p2=400/(m+300) 100=400/(1406.4382+300) 10023.4406



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