# Hole

In the center of the cube with edge 14 cm we will drill cylinder shape hole. Volume of the hole must be 27% of the cube. What drill diameter should be chosen?

Result

D =  8.2 cm

#### Solution:

$h=14 \ \\ V_1 = 0.27 \cdot V_2 \ \\ \pi(\dfrac{ D}{2} )^2 \cdot h = 0.27 \cdot h^3 \ \\ \ \\ D=2h\sqrt{ 0.27/\pi} = 8.2 \ \text{ cm }$

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