Feed to hay

How many tons of water do we have to dehydrate from 8 tons of feed if the original moisture is 54 percent to get hay with a moisture content of 15 percent? Round to two decimal places.

Correct answer:

x =  3.67 t

Step-by-step explanation:

m1=8 t p1=54%=10054=5027=0.54 p2=15%=10015=203=0.15  v1=p1 m1=0.54 8=25108=4.32 t s=m1v1=84.32=2592=3.68 t   p2 = v2 / (s+v2)  p2 (s+v2)=v2 0.15 (3.68+v2)=v2  0.85v2=0.552  v2=0.850.552=0.64941176  v2=4252760.649412  x=v1v2=4.320.6494=853123.6706 t   Verifying Solution:   p2  = s+v1yv1y  p2 (s+v1y)=v1y 0.15 (3.68+4.32y)=4.32y  0.85y=3.12  y=0.853.12=3.67058824  y=853123.670588  y=x

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