Feed to hay

How many tons of water do we have to dehydrate from 8 tons of feed, if the original moisture is 54 percent, to get hay with a moisture content of 15 percent? Round to two decimal places.

Correct answer:

x =  3.67 t

Step-by-step explanation:

m1=8 t p1=54%=54100=0.54 p2=15%=15100=0.15  v1=p1 m1=0.54 8=10825=4.32 t s=m1v1=84.32=9225=3.68 t  p2=v2/(s+v2)  p2 (s+v2)=v2 0.15 (3.68+v2)=v2  0.85v2=0.552  v2=2764250.649412  x=v1v2=4.320.6494=3.67 t

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