The gable

The house's gable is an isosceles triangle with a base length of 14 meters and arms lengths of 8 meters. What is the tall gable of the house?

Final Answer:

h =  3.873 m

Step-by-step explanation:

$$\begin{gathered} a=14\text{m} \\ r=8\text{m} \\ {r}^2=h^2+(a/2{)}^2 \\ h=\sqrt{r^2-(a/2{)}^2}=\sqrt{8^2-(14/2{)}^2}=\sqrt{15}=3.873\text{m} \end{gathered}$$

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