Linear function

What is the equation of linear function passing through points:

a) A (0,3), B (3,0)
b) C (-2,-6), D (3,4)

Final Answer:

y1 = -x+3
y2 = 2x-2

Step-by-step explanation:

y1​=f(x) = q⋅ x+w  A=(0,3) B=(3,0)  Ay​=q⋅ Ax​+w By​=q⋅ Bx​+w 3=q⋅ 0+w 0=q⋅ 3+w  w=3 3q+w=0  Pivot:Row1↔Row2  q=30−w​=30−3​=−1  q=−1  y1​=q x + w y1​=−x+3
y2​=f(x) = m⋅ x+n C=(−2,−6) D=(3,4)  Cy​=m⋅ Cx​+n Dy​=m⋅ Dx​+n (−6)=m⋅ (−2)+n 4=m⋅ 3+n  2m−n=6 3m+n=4  Pivot:Row1↔Row2  Row2−32​⋅ Row1→Row2 −1.67n=3.33  n=−1.666666673.33333333​=−2 m=34−n​=34+2​=2  m=2 n=−2  y2​=m x + n y2​=2x−2

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geometryalgebrabasic operations and conceptsGrade of the word problem

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