Square

Danov's father has a square of 65.25 milligram square of wire with a diagonal. How will the square be big when one mm weighs 7 mg?

Correct answer:

a =  1.7217 mm

Step-by-step explanation:

$$\begin{gathered} o_1=65.25\text{ mg } \\ h=7\text{ mg/mm } \\ o=o_1\mathrm{/}h=65.25\mathrm{/}7={\displaystyle \frac{261}{28}}\doteq 9.3214\text{ mm } \\ o=4a+u=4a+\sqrt{2}a \\ a=o\mathrm{/}(4+\sqrt{2})=9.3214\mathrm{/}(4+\sqrt{2})=1.7217\text{ mm} \end{gathered}$$

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