Square

Danov's father has a square of 65.25 milligram square of wire with a diagonal. How will the square be big when one mm weighs 7 mg?

Result

a =  1.722 mm

Solution:

o1=65.25 mg h=7 mg/mm o=o1/h=65.25/7≐26128≐9.3214 mm o=4a+u=4a+2a a=o/(4+2)=9.3214/(4+2)≐1.7217≐1.722 mmo_{1}=65.25 \ \text{mg} \ \\ h=7 \ \text{mg/mm} \ \\ o=o_{1} / h=65.25 / 7 \doteq \dfrac{ 261 }{ 28 } \doteq 9.3214 \ \text{mm} \ \\ o=4a +u=4a + \sqrt{ 2 } a \ \\ a=o / (4+\sqrt{ 2 })=9.3214 / (4+\sqrt{ 2 }) \doteq 1.7217 \doteq 1.722 \ \text{mm}

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